Check Whether Given Number is Armstrong or Not in C Program

It is a sample c program to check whether given number is Armstrong or not.

Program Source Code

#include"stdio.h"
#include"conio.h"
#include"math.h"
void main()
{
int number, a , i , j , sum=0 , count=0;
clrscr();
printf(“Enter any number”);
scanf(“%d”, &number);
i=number;
j=number;
while(j>0)
{
j=j%10;
count++;
}
while(i>0)
{
a=i%10;
sum=sum + pow(a, count);
i=i/10;
}
if(sum==number)
printf(“%d is a Armstrong number”, number);
else
printf(“%d is a not Armstrong number”, number);
getch();
}

Output

C Program for Check Armstrong Number

It is a sample C program to find accepted number is Armstrong number on not.


Program Source Code

//Write a program to check accepted number is armstrong number or not.
#include"stdio.h"
#include"conio.h"
void main()
{
  int i,no,r,sum=0;
  clrscr();
  printf("*******Armstrong Number******");
  printf("\n Enter a number");
  scanf("%d",&no);
  i=no;
  while(no!=0)
   {
    r=no%10;
    sum=sum+(r*r*r);
    no=no/10;
   }
   if(sum==i)
    printf("Number is a Armstrong number\n");
   else
    printf("Number is not a armstrong number\n");
   getch();
}

Output

Check Number is Armstrong in PL/SQL Programming

It is a sample pl/sql program to take input a number from user and it checks accepted number is Armstrong or not.

Aim - PL/SQL program to check whether number is Armstrong or not.

Program:-

declare
  pnum number(5);
  tot number(5);
  lp number(3);
  tmp number(5);
begin
  pnum:=&pnum;
  tmp:=pnum;
  tot:=0;
  while tmp>0
  loop
    lp:=tmp mod 10;
    tot:= tot + (lp*lp*lp);
    tmp:=floor(tmp/10);
  end loop;
  if(tot like pnum) then
    dbms_output.put_line(pnum||' is armstrong.');
  else
    dbms_output.put_line(pnum||' is not armstrong.');
  end if;
end;

Output: -
Enter value for pnum: 153
old 7: pnum:=&pnum;
new 7: pnum:=153;
153 is armstrong.